iconv() [function.iconv]: Detected an illegal character in

| | 2012/07/09 08:56 , mdy
PHP , 评论(0) , 阅读(1498) , Via 本站原创
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解决方法:
iconv('UTF-8', 'GB2312//IGNORE', '囧')
iconv('UTF-8', 'GBK', '囧')
或者是编码不对,或者增加抑制符@